So, I'm trying to solve this: \(\begin{pmatrix} 4\\ 3 \end{pmatrix} (2x-1)=-12\)

Do I multiply both sides by the recriprical of 4/3 or do I distribute first?

Thanks!

Guest Oct 13, 2018

#1**+1 **

Multiply both sides by 3/4 to get 2x-1=-9. Add 1 from both sides to get 2x=-8. Dividing both sides by 2 you get x as -4.

Guest Oct 13, 2018

#2**+1 **

Its [4!/3!(4-3)!](2x-1)=-12 <=>

<=> 24/6(2x-1)=-12 <=>

<=> 4(2x-1)=-12 <=>

<=> 8x-4=-12 <=>

<=> 8x=-8 so x=-1

I hope to helped you!

Dimitristhym Oct 13, 2018

#4**0 **

The 1st guest who answered was correct, the solution is \(x=-4\) (I checked). Thanks for the quick help!

Guest Oct 13, 2018

#5**+1 **

Oh im sorry i understand 4 choose 3 because you write it like this :( Im sorry !

Dimitristhym
Oct 13, 2018