So, I'm trying to solve this: \(\begin{pmatrix} 4\\ 3 \end{pmatrix} (2x-1)=-12\)
Do I multiply both sides by the recriprical of 4/3 or do I distribute first?
Thanks!
Multiply both sides by 3/4 to get 2x-1=-9. Add 1 from both sides to get 2x=-8. Dividing both sides by 2 you get x as -4.
+343 Its [4!/3!(4-3)!](2x-1)=-12 <=>
<=> 24/6(2x-1)=-12 <=>
<=> 4(2x-1)=-12 <=>
<=> 8x-4=-12 <=>
<=> 8x=-8 so x=-1
I hope to helped you!
The 1st guest who answered was correct, the solution is \(x=-4\) (I checked). Thanks for the quick help!
+343 Oh im sorry i understand 4 choose 3 because you write it like this :( Im sorry !
