to find axis of symmetry x= -b/2a how do you know which is a and b in a turning point equation such as 2(x-3)2^ - 2
+37084 First, expand your given equation
2(x-3)^2 - 2
2 (x^2 - 6x +9) -2 =
2x^2 -12x + 16 = 0 Simplify by dividing by '2';
x^2 -6x+8=0 NOW do you see what a,b,c are????
