”Twenty men did one-fourth of a job in eight days. Then it became necessary to complete the job in the next five days. How many additional men were added to the crew of twenty to accomplish the task?”
+129840 I like to call this type of problem a "see-saw" problem.
If 20 men finish 1/4 of a job in 8 days, it will take them 24 more days to do the job. Then, the question is how many men would it take to finish the job in 5 days?? So we have....
20 men*24 days = x men * 5 days
x = 20*24/5 = 96 men could finish the job in 5 days. But since we alreafy have 20 men, we need 76 additiomal men.....!!!!
If it took 20 men, 8 days to complete 1/4 of the work, then the total job requires 4x8dayx20men=640 man-days. If you have 3/4 of the job to go, then you require 0.75x640 = 480 man-days left to complete the job. If you have only 5 days left, then 480 man-days/5 days = 96 men. Easy pieze, Cheers Ty
So yes 76 more men, for a total crew of 96 men. I always forget to read the fine print.
+129840 I like to call this type of problem a "see-saw" problem.
If 20 men finish 1/4 of a job in 8 days, it will take them 24 more days to do the job. Then, the question is how many men would it take to finish the job in 5 days?? So we have....
20 men*24 days = x men * 5 days
x = 20*24/5 = 96 men could finish the job in 5 days. But since we alreafy have 20 men, we need 76 additiomal men.....!!!!
