two angles with a sine ratio of -0.93969 range is 0° ≤ x ≤ 360°

Look here:

http://tube.geogebra.org/student/m65299

Gruß radix !

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left(-{\mathtt{0.939\: \!69}}\right)} = -{\mathtt{69.999\: \!560\: \!966\: \!236^{\circ}}}$$

Let's call it -70°.  Sine is negative in the third and fourth quadrants, so the angles are  360°-70° and 180°+70°

or 290° and 250°

Check:

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\mathtt{290}}^\circ\right)} = -{\mathtt{0.939\: \!692\: \!620\: \!786}}$$  

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\mathtt{250}}^\circ\right)} = -{\mathtt{0.939\: \!692\: \!620\: \!786}}$$

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I do not understand what you are trying to show with this graph Radix