+0

Two containers designed to hold water are side by side, both in the shape of a cylinder.

0
487
2

Container A has a diameter of 8 feet and a height of 15 feet. Container B has a diameter of 12 feet and a height of 7 feet. Container A is full of water and the water is pumped into Container B until Container A is empty.

To the nearest tenth, what is the percent of Container B that is empty after the pumping is complete?

play

Apr 26, 2020

#1
+1

Volume of Cylinder A is                          pi times the area of the base times the height

π r2 h = (3.1416)(4)(4)(15) = 753.98 ft3

Volume of Cylinder B is likewise             pi times the area of the base times the height

π r2 h = (3.1416)(6)(6)(7)   = 791.68 ft3

After pumping all of Cyl A into Cyl B

there will remain empty space in B         791.68 – 753.98 = 37.7 ft3

The percentage this empty space is

of the entire volume is                            37.7 / 791.68 = 0.0476 which is 4.8% when rounded to the nearest tenth

.

Apr 26, 2020
edited by Guest  Apr 26, 2020
#2
+1

Checking back, I see that I made an error

It should not say the volume is    "pi times the area of the base times the height"

It should say                                "the area of the base times the height"

pi Is already figured in to the area

I know that I'm susceptible to clumsy errors like this, and I promise I proofread it several times before I finally clicked the publish button.  ~ sigh ~

.

Guest Apr 27, 2020