Container A has a diameter of 8 feet and a height of 15 feet. Container B has a diameter of 12 feet and a height of 7 feet. Container A is full of water and the water is pumped into Container B until Container A is empty.

To the nearest tenth, what is the percent of Container B that is empty after the pumping is complete?

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Guest Apr 26, 2020

#1**+1 **

Volume of Cylinder A is pi times the area of the base times the height

π r^{2} h = (3**.**1416)(4)(4)(15) = 753**.**98 ft^{3}

Volume of Cylinder B is likewise pi times the area of the base times the height

π r^{2} h = (3**.**1416)(6)(6)(7) = 791**.**68 ft^{3}

After pumping all of Cyl A into Cyl B

there will remain empty space in B 791**.**68 – 753**.**98 = 37**.**7 ft^{3}

The percentage this empty space is

of the entire volume is 37**.**7 / 791**.**68 = 0**.**0476 which is **4.8%** when rounded to the nearest tenth

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Guest Apr 26, 2020

edited by
Guest
Apr 26, 2020

#2**+1 **

Checking back, I see that I made an error

It should not say the volume is "pi times the area of the base times the height"

It should say "the area of the base times the height"

pi Is already figured in to the area

I know that I'm susceptible to clumsy errors like this, and I promise I proofread it several times before I finally clicked the publish button. ~ sigh ~

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Guest Apr 27, 2020