two dice are rolled. what is the probability that the total number achieved is greater than 4 but less than or equal to ten?
Probabiltiy of 5 = 4/36
Probabiltiy of 6 = 5/36
Probabiltiy of 7 = 6/36
Probabiltiy of 8 = 5/36
Probabiltiy of 9 = 4/36
Probabiltiy of 10 = 3/36
So ...the probabilty of > 4 but ≤ 10 = [ 4 + 5 + 6 + 5 + 4 + 3 ] / 36 = 27/36 = 3/4
two dice are rolled.
what is the probability that the total number achieved
is greater than 4 but less than or equal to ten?
\(\color{green}{\text{In green dice one}}\\ \color{blue}{\text{In blue dice two}}\\ \color{red}{\text{In red the total number } >4 \text{ and } \le 10 }\)
\(\begin{array}{|r|r|r|r|r|r|r|} \hline + & \color{blue}1 & \color{blue}2 & \color{blue}3 & \color{blue}4 & \color{blue}5 & \color{blue}6 \\ \hline \color{green}1 & 2 & 3 & 4 & \color{red}5 & \color{red}6 & \color{red}7 \\ \hline \color{green} 2 & 3 & 4 & \color{red}5 & \color{red}6 & \color{red}7 & \color{red}8 \\ \hline \color{green}3 & 4 & \color{red}5 & \color{red}6 & \color{red}7 & \color{red}8 & \color{red}9 \\ \hline \color{green}4 & \color{red}5 & \color{red}6 & \color{red}7 & \color{red}8 & \color{red}9 & \color{red}10 \\ \hline \color{green}5 & \color{red}6 & \color{red}7 & \color{red}8 & \color{red}9 & \color{red}10& 11 \\ \hline \color{green}6 & \color{red}7 & \color{red}8 & \color{red}9 & \color{red}10& 11& 12 \\ \hline \end{array} \)
\(\text{The probability of } > 4 \text{ but } \le 10 \text{ is } \dfrac{27}{36} \text{ or } 75\ \% \)