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If m is a real number and 2x^2 + mx + 18 has two distinct real roots, then what are the possible values of m? Express your answer in interval notation.

 Dec 3, 2020
 #1
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2x^2  +  mx    +  18

 

If we have two distinct rooots.....then the discriminant must  be >  0

 

So

 

m^2  - 4(2)(18)  >  0

 

m^2  - 144 >  0

 

m^2  >   144

 

The solutions  for  m  are    ( -inf, -12)   U  ( 12  ,inf )

 

 

cool cool cool

 Dec 3, 2020

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