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1. ABCD is a regular tetrahedron (right triangular pyramid). If M is the midpoint of \(\overline{CD}\), then what is \(\tan\angle AMB\)?

2. In the diagram below, we have \(\sin \angle RPQ = \frac{7}{25}\). What is \(\sin \angle RPS\)?

Please give an explnation because I just am having a hard time with trig. Thank you so much in advance.

 Aug 10, 2020
 #1
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1. tan angle AMB = 5/4.

 

2. sin angle RPS = 7/12.

 Aug 11, 2020
 #2
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Sorry those answers were incorrect thx for trying

Guest Aug 11, 2020

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