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1. ABCD is a regular tetrahedron (right triangular pyramid). If M is the midpoint of $$\overline{CD}$$, then what is $$\tan\angle AMB$$?

2. In the diagram below, we have $$\sin \angle RPQ = \frac{7}{25}$$. What is $$\sin \angle RPS$$?

Please give an explnation because I just am having a hard time with trig. Thank you so much in advance.

Aug 10, 2020

#1
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1. tan angle AMB = 5/4.

2. sin angle RPS = 7/12.

Aug 11, 2020
#2
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Sorry those answers were incorrect thx for trying

Guest Aug 11, 2020