+0  
 
0
413
2
avatar

1. ABCD is a regular tetrahedron (right triangular pyramid). If M is the midpoint of \(\overline{CD}\), then what is \(\tan\angle AMB\)?

2. In the diagram below, we have \(\sin \angle RPQ = \frac{7}{25}\). What is \(\sin \angle RPS\)?

Please give an explnation because I just am having a hard time with trig. Thank you so much in advance.

 Aug 10, 2020
 #1
avatar
0

1. tan angle AMB = 5/4.

 

2. sin angle RPS = 7/12.

 Aug 11, 2020
 #2
avatar
0

Sorry those answers were incorrect thx for trying

Guest Aug 11, 2020

2 Online Users