1. https://web2.0calc.com/questions/pls-help_14236

2. A geometric sequence of positive integers is formed for which the first term is 2 and the fifth term is 162. What is the sixth term of the sequence?

AnimalMaster Jul 17, 2020

#1**+1 **

2) first term is 2 which is multiplied by the common ratio 4 times to get the 5th term = 162

2 * r^{4} = 162

r = 3

to get from the 5th term to the sixt term multiply by the ratio, 3 162 x3 = 486

ElectricPavlov Jul 17, 2020