The first and ninth terms of an arithmetic sequence are 2/3 and 4/5, respectively. What is the fifth term?
Thanks so much for all the help!
Nth term = First term + [Number of term - 1] x Common difference.
So, the 9th term is:
4/5 = 2/3 + [9 - 1] x D, solve for D
4/5 - 2/3 = 8D
[12 - 10] / 15 = 8D
2/15 = 8D
D = 1/60
5th term = 2/3 + [5 - 1] x 1/60
= 2/3 + 4/60
=2/3 + 1/15
=11 / 15, which is the 5th term of this sequence.
Nth term = First term + [Number of term - 1] x Common difference.
So, the 9th term is:
4/5 = 2/3 + [9 - 1] x D, solve for D
4/5 - 2/3 = 8D
[12 - 10] / 15 = 8D
2/15 = 8D
D = 1/60
5th term = 2/3 + [5 - 1] x 1/60
= 2/3 + 4/60
=2/3 + 1/15
=11 / 15, which is the 5th term of this sequence.