The first and ninth terms of an arithmetic sequence are 2/3 and 4/5, respectively. What is the fifth term?

Thanks so much for all the help!

AnonymousConfusedGuy Jan 8, 2018

edited by
Guest
Jan 8, 2018

#1**+1 **

Nth term = First term + [Number of term - 1] x Common difference.

So, the 9th term is:

4/5 = 2/3 + [9 - 1] x D, solve for D

4/5 - 2/3 = 8D

[12 - 10] / 15 = 8D

2/15 = 8D

D = 1/60

5th term = 2/3 + [5 - 1] x 1/60

= 2/3 + 4/60

=2/3 + 1/15

** =11 / 15, which is the 5th term of this sequence.**

Guest Jan 8, 2018

#1**+1 **

Best Answer

Nth term = First term + [Number of term - 1] x Common difference.

So, the 9th term is:

4/5 = 2/3 + [9 - 1] x D, solve for D

4/5 - 2/3 = 8D

[12 - 10] / 15 = 8D

2/15 = 8D

D = 1/60

5th term = 2/3 + [5 - 1] x 1/60

= 2/3 + 4/60

=2/3 + 1/15

** =11 / 15, which is the 5th term of this sequence.**

Guest Jan 8, 2018