Hello. Can anyone help me with this problem? I need to resolve but I can not at all. Please, I need the step-by-step resolution, or at least the beginning. I can not get out of the statement. Thanks.
6600+0,0075X = X * (1+y*(28/12))
Thanks.
It's a Financial Calculation problem.
A certain capital applied in simple interest at the annual rate during 27 months produced the accumulated capital of 6600 €. If the same capital was applied at the same rate but for 28 months, the cumulative capital reference would be increased by an amount corresponding to 0.75% of the initial capital. Calculate the starting capital and the annual rate to which it was applied.
I arrived at the initial formula, but then I do not know how to solve:
Equity = Initial Capital * (1 + rate * time), this is the calculation formula for accumulated capital.
6600 + 0,0075C0 = C0 * (1 + i * (28/12))
Little remark: I am Portuguese.
OK, your problem is not stated very clearly! But, as far as I can understand you, this is what I think your problem is:
If the initial Capital was C, then you have:
C x i% x 27 = 6,600..........................................(1)
C x i% x 28 = 6,600 + 0.0075C.........................(2), solve for i% and C
i =0.0075 pe month!!, and: 0.0075 x 12 x 100 =9% annual simple interest.
C=32,592.60 - Euros - The initial capital.
NOTE: I used SIMPLE INTEREST and not COMPOUND INTEREST, because your question says" applied 'simple interest'". Give us some feedback, so that we can help you solve the problem.
+9466 Here's my best guess, but I could easily be wrong.....
Let c be the starting capital, and let i be the annual interest rate.
accumulated capital after 27 months = c(1 + i * 27/12) = 6600
accumulated capital after 28 months = c(1 + i * 28/12) = 6600 + 0.75% * c
Now we have two equations and two variables.
c(1 + i * 28/12) = c(1 + i * 27/12) + 0.75% * c Divide through by c .
1 + i * 28/12 = 1 + i * 27/12 + 0.75% Subtract 1 from both sides.
i * 28/12 = i * 27/12 + 0.75% Subtract i * 27/12 from both sides.
i * 1/12 = 0.75% Multiply both sides by 12 .
i = 9%
If I have interpreted the question correctly, this makes sense because it tells you that an additional month of interest adds 0.75% of the capital. That means that 0.75% is the annual rate / 12 . I might have not interepreted the question correctly.
Now....using this value of i , we can find c .
c(1 + 9% * 27/12) = 6600
c( 1.2025 ) = 6600 Divide both sides of the equation by 1.2025 .
c ≈ 5488.57
Thank you very much for the help! That's it. 
I'll enjoy it for a while, without wanting to abuse 
- A capital of € 7000 was applied on a flat-rate basis at the half-yearly rate of 4% over a given period and produced an accumulated capital of more than € 1,400 to that which would be obtained if the period was reduced by half. Calculate the term of capital application.
+9466 Okay, I'll give this one a try also...
Let t be the number of 6 month periods in the term.
7000( 1 + 4% * t ) = 1400 + 7000( 1 + 4% * t/2 )
Divide through by 7000.
1 + 4% * t = 0.2 + 1 + 4% * t/2
Subtract 1 from both sides.
4% * t = 0.2 + 4% * t/2
Subtract 4% * t/2 from both sides.
4% * t - 4% * t/2 = 0.2
t(4% - 4% / 2) = 0.2
t(4% - 2%) = 0.2
t( 2% ) = 0.2
t = 0.2 / ( 2% ) = 10
There were 10 periods of 6 months in the term. That is 5 years.
