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(2-(sec^2)(x))/((sec^2)(x))

 Apr 1, 2016
 #1
avatar+1904 
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Type it in Calc like this: \(2-(sec(x))^2/(sec(x))^2\)

 Apr 1, 2016
 #2
avatar+118690 
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(2-(sec^2)(x))/((sec^2)(x))

 

You have brackets in nonsense places.  So no calc will accept it like that !

 

Anyway

You could just simplify it yourself :/

 

\(\frac{2-(sec^2x)}{sec^2(x)}\\ =[2-\frac{1}{cos^2x}]\div sec^2(x)\\ =[\frac{2cos^2(x)-1}{cos^2x}]\times cos^2(x)\\ =[\frac{2cos^2(x)-1}{1}]\\ =2cos^2(x)-1\\ =cos^2(x)+cos^2(x)-1\\ =cos^2(x)-(-cos^2(x)+1)\\ =cos^2(x)-sin^2(x)\\ =cos(2x)\)

 

 

 

 

I typed it into the web2 calc but the calc did not simplify it

 

(2-(sec(x))^2)/((sec(x)^2) = ((2-((sec(x))^2))/(sec(x))^2)

 Apr 1, 2016

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