OK, I'm going through my lab final - I'm having a difficult time with ALL OF IT...LOL Yes, I'm not good at higher math. And this is probably basic algebra....
My question is x-2x^1/2-3= 0 and use u substitution. My answer is x=9
x- 2x^(1/2) - 3= 0
Let x = u^2 ...so.....x^(1/2) = u and we have
u^2 - 2u - 3 = 0 factor
(u - 3) ( u + 1) = 0 set both factors equal to 0 and solve
u - 3 = 0 u + 1 = 0
add 3 to both sides subtract 1 from both sides
u = 3 u = -1
So
u^2 = 3^2 = 9 = x or u^2 = (-1)^2 = 1 = x
The second solution makes the original problem false......so...... x = 9 is the only solution