Let and be the roots of y^2 + 5y - 11 = 0. Find (a + 3)(b + 3).
By the quadratic formula, the roots are (-5 +- sqrt(69))/2, so the answer is ((-5 + sqrt(69)/2 + 3)((-5 - sqrt(69)/2 + 3) = -13.
Thank you so much, but I entered the answer after checking if it was correct, and it still says it was wrong...
Let a and b be the roots of \(y^2+5y-11=0\)
\((a+3)(b+3)\) Expand this.
\(ab+3a+3b+9\) Factor 3 from middle terms
Now substitute the values
Vieta's formula states that:
for any quadratic equation (Even for any polynomial )
With roots: \((x_1,x_2)\)
Does it work for cubic equation?
with roots: \((y_1,y_2,y_3)\)