Find the Sum of All Solutions to
(log2x)(log3x)(log4x)(log5x)=(log2x)(log3x)(log4x)+(log2x)(log3x)(log5x)+(log2x)(log4x)(log5x)+(log3x)(log4x)(log5x).
Here's one solution:
(Of course, you don't have to use base 60; any base would do - but I only thought of this after doing the above!).
.
+116 
