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Find the Sum of All Solutions to 

 

(log2x)(log3x)(log4x)(log5x)=(log2x)(log3x)(log4x)+(log2x)(log3x)(log5x)+(log2x)(log4x)(log5x)+(log3x)(log4x)(log5x).

 Mar 30, 2019
 #1
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+3

Here's one solution:

 

 

(Of course, you don't have to use base 60; any base would do - but I only thought of this after doing the above!). 

.

 Mar 31, 2019
edited by Alan  Mar 31, 2019
edited by Alan  Mar 31, 2019
edited by Alan  Mar 31, 2019

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