how do you put y= x2 + 6x + 10 into vertex form????
y = x^2 + 6x + 10
Take (1/2) the coefficient on x = (1/2)(6) = 3 .....square it = 9 .....add and subtract this
y = x^2 + 6x + 9 + 10 - 9 simplify
y = x^2 + 6x + 9 + 1 factor the first three terms as a perfect square
y = (x + 3) ^2 + 1
The vertex is ( -3, 1)
