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# Undecimal

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Find how many digits the base ten number 11^8^5 has when written in base eleven.

I have an answer but I'm not sure if it's right because the question is kind of confusing to me.

Feb 24, 2021

#1
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11^(8^5) in base 11 ==1.1062AA481 E+33957

It has: 33,957 + 1 ==33, 958 digits in base 11

Feb 24, 2021
#2
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I got 2268a base 11 digits... I'm not sure how you calculated it but I used Melody's answer as a guide and this is what I got?

https://web2.0calc.com/questions/find-how-many-digits-in-the-base-10-number-9-9-9

Logarhythm  Feb 24, 2021
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i asked this question awhile ago, someone got an answer dont know if its right tho https://web2.0calc.com/questions/find-how-many-digits-the-base-ten-number-11-8-5

Guest Feb 24, 2021
#3
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It will have 8^5 zeros plus a 1 at the front

that is 32768+1 = 32769 digits

(the numbers on the left are in base 10 and the numbers on the right are in the given base)

10^4 = 10000 base 10

5^2 = 100 base 5

7^6 = 1000000 base 7

3^2 = 100 base 3

Feb 24, 2021
edited by Melody  Feb 24, 2021
#5
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Thank you!

Logarhythm  Feb 24, 2021
#7
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You are very welcome. Melody  Feb 24, 2021
#4
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Convert: 10^(8^5) from base 10 to base 11

Answer: 1E32,768 ==32768 + 1 =32,769 digits in base 11

Feb 24, 2021