Given that sin(32 degrees) = a and cos(32 degrees) = b, find tan(148 degrees) in terms of a and/or b.
+36916 SIn (pi - 32) = sin 32 so sin 148 = sin32 = a
cos(pi-32) = -cos(32) so cos(148) = -b
tan (148) = sin(148) / cos(148) = -a/b
+36916 SIn (pi - 32) = sin 32 so sin 148 = sin32 = a
cos(pi-32) = -cos(32) so cos(148) = -b
tan (148) = sin(148) / cos(148) = -a/b
