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In this question: The domain of the function h(x) = sqrt(25-x^2) + sqrt(-(x-2) is an interval of what width?

 

I think the domain is: [2, -5], so in total, 8 terms satisfy the domain, so is the with 8? Because apparently it's not...can someone explain this to me?

Guest Apr 25, 2018
 #1
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√[25 - x^2 ] + √[ - ( x - 2) ]  =

 

√[25 - x^2 ]  + √ [2 - x ]

 

The domain for the first function  is  [ -5, 5 ]

 

The domain for the second function is  ( - infinity, 2]

 

Because  we must take the most restrictive interval, this is   [ -5, 2 ]

 

So....the width of the interval  is  7 units   [ 8 integers ]

 

So the graph, here : https://www.desmos.com/calculator/ioiruyyh4v

 

 

cool cool cool

CPhill  Apr 25, 2018
edited by CPhill  Apr 25, 2018

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