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Given triangle ABC, FC is parallel to BA, and AF bisects <BAC Prove AB/BD=AC/CD

1. △ABC , FC ∥BA , and AF bisects ∠BAC            Given

2. ∠BAD≅∠CAD                                                    

3. ∠BAD≅∠CFD                                                     Alternate Interior Angles Theorem

4. ∠CFD≅∠CAD                                                     Substitution Property

​5.                                                                              Vertical angles are congruent.

6. △ADB∼△FDC                                                    Angle Angle Similarity Postulate

7. AB/BD=FC/CD                                                     Definition of similar triangles

8. AC=FC                                                                 Converse of Base Angles Theorem

9.                                                                              Definition of congruent angles

For 2,5, and 9, here are the choices (one for each).

-Def. of angle bisector

-<ADB~/=<CDF

-Def. of congruent angles

-Angle addition postulate

-<BAD~/=<CAD

-Substitution Property

 Feb 6, 2017
 #1
avatar+129839 
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2. -Def. of angle bisector

 

5. -<ADB~/=<CDF

 

Unsure about 9

 

 

cool coolcool

 Feb 6, 2017
 #2
avatar+9665 
0

We have less things to do....... Hong Kong have a different version of geometric proof......

 

Let me do this in my version.

 

\(\begin{array}{lr}1.\angle\text{BAD}=\angle\text{CAD}&\text{angle bisector}\\2.\angle\text{BAD}=\angle\text{CFD}&\text{alt.}\angle s,AB//CF\\\quad\therefore\angle \text{CAD} = \angle \text{CFD}\\ 3.\text{CA}=\text{FC}&\text{sides. opp.,eq. }\angle s\\ 4.\angle\text{ADB}=\angle\text{CDF}&\text{vert. opp. }\angle s\\ 5.\angle\text{ABD}=\angle\text{FCD}&\text{alt.}\angle s,\;AB//CF\\ 6.\triangle\text{ABD}\sim\triangle\text{FCD}&\text{A.A.A.}\\ 7.\dfrac{\text{AB}}{\text{BD}}=\dfrac{\text{FC}}{\text{CD}}&\text{corr. sides,}\sim \triangle s\\ 8.\dfrac{\text{AB}}{\text{BD}}=\dfrac{\text{AC}}{\text{CD}}\end{array}\)

 

We don't need to write the below stuff but it is just a explanation for you.

 

\(\text{alt. }\angle s,\text{AB}//\text{CD}\) means the alternate interior angles of the 2 parallel lines AB and CD. (Yes we use // instead of ||)We don't have alternate exterior angles so if you write alt. angles it must mean alternate interior angles. (So that the proof for alternate exterior angles are more complicated. LOL)

 

The reason "angle bisector" just means "definition of angle bisectors".

 

sides opp., eq angles means when the base angles are equal, that triangle is a isosceles triangle. Don't ask me why "opp.". I don't know. My teacher neither.

 

A.A.A. is the Angle Angle Similarity Postulate. A.A.A. means Angle Angle Angle. We have to prove both 3 angles are equal to prove similarity.

 

corr. sides similar triangles means "the corresponding sides of similar triangles are equal."

 

As you see:

 

1) We use \(=\) instead of \(\cong\) for angles because the congruent symbol for representing triangle congruency. And we use // instead of ||

 

2) We have different reasons.

 

3) We do not need to write any reasons for some lines. No reason is just blank. You don't need to put something like 'Substitution Property'.

 Feb 6, 2017

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