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if N = (11^p+7)(7^q-2)(5^r+1)(3^s) and N ia perfect cube where p,q,r,s are positive integers.

find the smallest value of p+q+r+s .

Darkside  Aug 11, 2018
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Is   (11^p+7)        \(11^p+7 \qquad\text { or is it } \qquad11^{p+7}\qquad ?\)

 

so   ((11^p)+7) or   (11^(p+7))

Melody  Aug 14, 2018
edited by Melody  Aug 14, 2018

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