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From the following infinite list of numbers, how many are integers? $$sqrt{4096},\sqrt[3]{4096},\sqrt[4]{4096},\sqrt[5]{4096},\sqrt[6]{4096},\ldots$$

Oct 13, 2021

#1
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There are only three integers: $\sqrt{4096}$, $\sqrt[3]{4096}$, and $\sqrt[4]{4096}$.

Oct 13, 2021
#2
0

the '...' shows that its an infinite list

Guest Oct 13, 2021