If I have a 4x4 chess board, in how many ways can I place four distinct pawns on the board such that each column and row of the board contains no more than one pawn?
+128408 I think this is correct
We can place the first pawn in any column of the top row = 4 ways
For the second pawn....we can place it anywhere on the second row except in the column occupied by the first pawn = 3 ways
The third pawn can then be placed in any two positions on the third row....= 2 ways
And the last pawn, by default....only has 1 way it can be placed on the fourth row
So
4 x 3 x 2 x 1 = 24 ways
