If I have a 4x4 chess board, in how many ways can I place four distinct pawns on the board such that each column and row of the board contains no more than one pawn?

Guest Feb 2, 2019

#1**+1 **

I think this is correct

We can place the first pawn in any column of the top row = 4 ways

For the second pawn....we can place it anywhere on the second row except in the column occupied by the first pawn = 3 ways

The third pawn can then be placed in any two positions on the third row....= 2 ways

And the last pawn, by default....only has 1 way it can be placed on the fourth row

So

4 x 3 x 2 x 1 = 24 ways

CPhill Feb 2, 2019