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If I have a 4x4 chess board, in how many ways can I place four distinct pawns on the board such that each column and row of the board contains no more than one pawn?

 Feb 2, 2019
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I think this is correct

 

We can place the first pawn  in  any column of the top row  = 4 ways

 

For the second pawn....we can place it anywhere on the second row except in the column occupied by the first pawn = 3 ways

 

The third pawn can then be placed in any two positions on the third row....= 2 ways

 

And the last pawn, by default....only has 1 way it can be placed on the fourth row

 

So

 

4 x 3 x 2  x 1   =   24 ways

 

cool cool  cool

 Feb 2, 2019

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