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How do you solve (c)??

 Mar 5, 2022
 #1
avatar+1384 
+1

 I will try this one. 

 

There are 3 cases to consider: 

 

1) He rolls a sum of 3 on the first turn

2) He rolls a sum greater than 3 on the first turn, and then he rolls a sum of 3

3) He rolls a sum of 2 that get him to 99 and then he rolls a sum of 4 

 

P(1)

 

He rolls: (2,1) or (1,2), meaning the probability is 2/36. 

 

P(2)

 

The first roll of getting a number greater than 3: 11/12. Second roll of rolling a 3: 1/18 This means the total probability is 11/12 x 1/18 = 11/216

 

P(3)

 

The probabilty of getting a 2 to get to 99: 1/36. The probability of getting a 4: 1/12. This means that teh total propbabilty is 1/36 x 1/12 = 1/432

 

Add em all up, and you find the total probability is \(\color{brown}\boxed{47\over 432}\)

 Mar 6, 2022

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