A marble is dropped a distance of 78.48 m. How long does it take to fall this far?
+6248 \(g = -9.8 ~m/s\\ h(t) = \dfrac{gt^2}{2} + v_0t+ h_0 = -4.9t^2 + 78.48\\ \text{at the end of it's fall the marble is at }h=0\\ 0=-4.9t^2 + 78.48\\ 4.9t^2 = 78.48\\ t^2 \approx 16.01632653\\ t \approx 4s\)
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+98 To figure this out you need to have the speed which the ball is traveling.
V=s/t
Volocity equals speed over time.
Volocity is in meters per second
