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In an equation of the form k=ax^2+bx+c with a>0, the least possible value of k occurs at x=-b/(2a). In the equation k=(6x+12)(x-8), what is the least possible value for k?

 Feb 23, 2020
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The least possible value of k is -4/(2*6) = -1/3.

 Feb 25, 2020

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