(2𝑥5−1/9𝑦4)5
a. Show the summation notation equation (with the correct value plugged in for n) used to express the expansion.
b. Using the equation you wrote in part a, use it to determine the third term of this expansion
Please Show All Work.
(2x^5 - (1/9)y^4)^5
a) Summation notation
5
Σ C(5,n) (2x5)(5-n) (-(1/9)y4)n
n = 0
(b) 3rd term =
C (5,2) * (2)3 x15 * (-(1/9y4)2 = 10 * (8x15) (1/81)y8 = (80/81)x15 y 8
+244 
