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avatar+244 

(2𝑥5−1/9𝑦4)5

 

a. Show the summation notation equation (with the correct value plugged in for n) used to express the expansion.

 

b. Using the equation you wrote in part a, use it to determine the third term of this expansion

 

Please Show All Work.

 Nov 28, 2020
 #1
avatar+114592 
+2

(2x^5 - (1/9)y^4)^5

 

a)  Summation notation

 

5

Σ  C(5,n)   (2x5)(5-n) (-(1/9)y4)n

n = 0

 

(b)   3rd term =

 

C (5,2) * (2)3 x15 * (-(1/9y4)2  =    10  * (8x15) (1/81)y8    =  (80/81)x15 y 8

 

 

cool cool cool

 Nov 28, 2020

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