use the first six terms to predict the limit of the sequence
a subtext n = n+6 / n^3 +6
(assume n begins with 1)
a. 1/6
b. 6
c. the sequence diverges
d. 0
e. 1
a subtext 1 = 7/7 = 1
a subtext 2 = 8/14 = 4/7
a subtext 3 = 9/33 = 3/11
a subtext 4 = 10/70 = 1/7
a subtext 5 = 11/131
a subtext 6 = 12/222 = 2/37
As it goes nearer and nearer to 0,
lim a subtext n = a subtext infinity = 0.
x-> infinity
Answer is d.
