use the quadratic formula to find the solution of the following quadratic equation to correct to two decimal places.
1)3x^2-4x-2=0
2) 2x^2+9x+1=0
3)5x^2+2x-4=0
+14986 use the quadratic formula to find the solution of the following quadratic equation to correct to two decimal places.
1)3x^2-4x-2=0
2) 2x^2+9x+1=0
3)5x^2+2x-4=0
1) \(3x^2-4x-2=0\)
a b c
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(x = {4 \pm \sqrt{16+24} \over 6}\)
\({\color{blue}x=\frac{4\pm\sqrt{40}}{6}}\)
x1 = 1.72 x2 = -0.39 
!
2) \(2x^2+9x+1=0\)
a b c
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(x = {-9 \pm \sqrt{81-8} \over 4}\)
\({\color{blue}x = {-9 \pm \sqrt{73} \over 4}}\)
x1 = -0.11 x2 = -4.39 !
3) \(5x^2+2x-4=0\)
a b c
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(x = {-2 \pm \sqrt{4+80} \over 10}\)
\({\color{blue}x=\frac{-2\pm\sqrt{84}}{10}}\)
x1 = 0.72 x2 = -1.12 !
\(\)
