Use the unit circle to find sin Θ.
A) √3
B) 1/2
C) √3/2
D) √3/3
E) 2
The triangle shown is an isosceles right triangle. What is the tangent of angle A?
A) 1
B) 2
C) √2
D) √2/2
E) 1/2
First one
Sin θ = y / r = [ √ 3/2 ] / 1 = √ 3 / 2
Second one
Since we have an isoceles right triangle , AB = BC
Tan A = BC / AB = AB / AB = 1
+1982 
