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using arithmetic sequences and recursive/explicit formula, how would i get the answer when asked to "find the sum of the first 12 terms of the given series?"  -  40+29+18+7+...

 Apr 30, 2015

Best Answer 

 #1
avatar+130516 
+5

The nth tem of an arithmetic series is given by :

an = a1 + d(n - 1)   where an is the term we're looking for, a1 is the first term of the series, d is the common difference between successive terms, and n is the number of terms of interest....so .....

The 12th term is given by :

a12 = 40 -11(12-1)  = 40 - 11(11)  =  40 - 121  = -81

 

  

 Apr 30, 2015
 #1
avatar+130516 
+5
Best Answer

The nth tem of an arithmetic series is given by :

an = a1 + d(n - 1)   where an is the term we're looking for, a1 is the first term of the series, d is the common difference between successive terms, and n is the number of terms of interest....so .....

The 12th term is given by :

a12 = 40 -11(12-1)  = 40 - 11(11)  =  40 - 121  = -81

 

  

CPhill Apr 30, 2015

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