Help, I get stuck when using snell's law. If 0.2858 = sin theta 2, how do you solve for theta 2?
I am not sure if I am answering your question but
0.2858 = sin theta 2
$$\\0.2858 = sin (\theta_2)\\\\
\theta_2=asin(0.2858)$$
$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\mathtt{0.285\: \!8}}\right)} = {\mathtt{16.606\: \!674\: \!357\: \!671^{\circ}}}$$
I am not sure if I am answering your question but
0.2858 = sin theta 2
$$\\0.2858 = sin (\theta_2)\\\\
\theta_2=asin(0.2858)$$
$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\mathtt{0.285\: \!8}}\right)} = {\mathtt{16.606\: \!674\: \!357\: \!671^{\circ}}}$$