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Help, I get stuck when using snell's law.  If 0.2858 = sin theta 2, how do you solve for theta 2? 

 Dec 17, 2014

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 #1
avatar+118723 
+5

I am not sure if I am answering your question but

0.2858 = sin theta 2

$$\\0.2858 = sin (\theta_2)\\\\
\theta_2=asin(0.2858)$$

 

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\mathtt{0.285\: \!8}}\right)} = {\mathtt{16.606\: \!674\: \!357\: \!671^{\circ}}}$$

 Dec 18, 2014
 #1
avatar+118723 
+5
Best Answer

I am not sure if I am answering your question but

0.2858 = sin theta 2

$$\\0.2858 = sin (\theta_2)\\\\
\theta_2=asin(0.2858)$$

 

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\mathtt{0.285\: \!8}}\right)} = {\mathtt{16.606\: \!674\: \!357\: \!671^{\circ}}}$$

Melody Dec 18, 2014

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