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Using the equation 2300(1.035)^x, when will the initial amount double?

Guest Feb 28, 2017
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2300(1.035)^x,

 

4,600 = 2,300 x 1.035^x

2 = 1.035^x take the log of both sides

x = Log(2) / Log(1.035)

x =20.15 years to double.

Guest Feb 28, 2017

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