Using the expression 2n-3+4n+6n+1 and using only ONE set of parentheses, where does the parentheses go if the expression must equal n+1

  Using the expression [2n-3+4n+6n+1] and using only ONE set of parentheses [(and)], where does the parentheses go if the expression must equal [n+1]? I have found that I must distrubute the [-3], but every way I try goes wrong. Example:

2(n-3)+4n+6n+1= 2n-6+4n+6n+1= 12n+[-5]

  And there are more, like {2n-(3+4n+6n)+1} which equals [-8n], another wrong answer. Again there are more wrong expressions! So... Please Help!