What constant is added to the RIGHT side of the quadratic equation 2x2 - 5x + ___ = 12 + ___ in order to solve by completing the square?
2x^2 - 5x - 12 = 0 factor out 2
2 [x ^2 - (5/2)x - 6] = 0 divide by 2
x^2 - (5/2)x - 6 = 0 add 6 to both sides
x^2 - (5/2)x = 6
Take (1/2) of (5/2) = (5/4) ....square this = 25/16....add to both sides
x^2 - (5/2)x + 25/16 = 6 + 25/16 mutliply back by 2
2x^2 - 5x + 25/8 = 12 + 25/8