Using the segment addition postulate, find the value of x.
AB = 3x + 8
BC = 4x + 6
AC = 28
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+1197 Using the rules of the segment addition postulate, we get (3x+8)+(4x+6)=28.
Combine like terms: 7x+14=28.
Subtract 14 from both sides: 7x=14.
Divide both sides by 7, and there's the value of x.
P.S, I hope you didn't mind me posting at the same time as you. I clicked publish, and yours popped up "0 min ago."
+129852 AB = 3x + 8
BC = 4x + 6
AC = 28
We have that AB + BC = AC ...therefore......
[3x + 8] + [4x + 6] = 28 simplify
7x + 14 = 28 subtract 14 from both sides
7x = 14 divide by 2 on both sides
x = 2
+1197 Using the rules of the segment addition postulate, we get (3x+8)+(4x+6)=28.
Combine like terms: 7x+14=28.
Subtract 14 from both sides: 7x=14.
Divide both sides by 7, and there's the value of x.
P.S, I hope you didn't mind me posting at the same time as you. I clicked publish, and yours popped up "0 min ago."
