Item 5
The terminal ray of ∠A passes through the point (10,−4) .
∠A is drawn in standard position.
What is the value of secA ?
Enter your answer as an exact answer, in simplified form, in the box.
x = 10
y = -4
r = sqrt (x^2 + y^2) = √ [ (10)^2 + (-4)^2) ] = √ [ 100 +16 ] = √[ 116 ] = √ [ 4 * 29] = 2 √29
sec A = r / x = 2 √ (29) / 10 = √29 / 5
+109 
