+0  
 
0
209
1
avatar+124 

 

Item 5

The terminal ray of  ∠A passes through the point  (10,−4) .

∠A  is drawn in standard position.

What is the value of  secA ?

Enter your answer as an exact answer, in simplified form, in the box.

 Feb 9, 2020
 #1
avatar+111396 
0

x = 10

y  = -4

r  =  sqrt  (x^2 + y^2)  = √   [  (10)^2  + (-4)^2) ]  = √ [ 100 +16 ]   = √[ 116 ]  = √ [ 4 * 29]  = 2 √29

 

sec A  =  r  / x    =    2 √ (29)  /  10   =     √29 / 5 

 

 

cool cool cool

 Feb 10, 2020

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