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I don't necessarily know what steps to take to solve this problem. I don't want to cube the denominator by hand as it will become very large quickly. My guess is something to do with the cube roots of 2 and 4 and combining them somehow from 1 + 2^(1/3) + 2^(2/3). 

 Mar 24, 2023
 #2
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Look at 1 + 2^(1/3) + 2^(2/3) and think arithmetic progression.

 Mar 24, 2023
 #3
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Thank you!

Guest Mar 25, 2023
 #4
avatar+397 
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You shouldn't.

I should have said geometric.

First term 1, common ratio 2^(1/3).

Tiggsy  Mar 25, 2023

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