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x+p+z+f+4 = 6

6/4 = x

p+z=f•f

 

p = ?

x = ?

z = ?

f = ?

or not enough info ?

 Jan 12, 2016
 #1
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x+p+z+f+4 = 6

6/4 = x

p+z=f•f

 

x+p+z+f+4 = 6

6/4 + f^2 + f + 4=6

f^2 + f=6-4-6/4

f^2 + f=1/2

Solve for f:
f^2+f = 1/2

Add 1/4 to both sides:
f^2+f+1/4 = 3/4

Write the left hand side as a square:
(f+1/2)^2 = 3/4

Take the square root of both sides:
f+1/2 = sqrt(3)/2 or f+1/2 = -sqrt(3)/2

Subtract 1/2 from both sides:
f = sqrt(3)/2-1/2 or f+1/2 = -sqrt(3)/2

Subtract 1/2 from both sides:
Answer: | f = sqrt(3)/2-1/2 or f = -1/2-sqrt(3)/2  f=.366  or   f=-1.366

x+p+z+f+4 = 6

x=6/4

p=.133956

z=.133956

f=.366

THERE COULD BE OTHER SOLUTIONS!!!!!!.

 Jan 12, 2016

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