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Hello!

So the other day I posted a question and I realized I forgot to give the image that is accompanied by the problem. Sorry.

Let V = (0,3,2) and A = (-1,0,1). Let P be the point on the line passing through A with direction vector (1,1,1) that is closest to V. Find \(\overrightarrow{AP} \)

 

 

https://docs.google.com/document/d/1MDPJY2ELXJeoMdy_YCeIbCpOCIq4Cr-TS8JfBP5bU20/edit?usp=sharing 

^ Image Link

 
 May 10, 2021
 #1
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AP = (4/3, -8/3, 16/3).

 May 11, 2021

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