+30 If vector B has a magnitude of 140 km and an angle of 65 above the positive x axis, does that mean vector -B has the same magnitude, but is 65 degrees below the positive x axis? And when you are finding the components for vector -B, would you use -65 as ø? For reference, here is part of the problem: The displacement from the control tower to plane 2 is given by the vector B⃗ , which has a magnitude of 140 km and points 65 ∘ east of north.
+33615 1. If vector B is has magnitude 140km and is 65° above the positive x axis then -B will have the same magnitude but will be 65° below the negative x axis (assuming the vector starts at (0, 0). i.e. both the x and y coordinates will be reversed.
2. 65° East of North is 25° above the positive x-axis!
+118608 That sounds right to me but I don't know about vectors.
Can someone knowledgable take a lquick look at this query please. :))
+33615 1. If vector B is has magnitude 140km and is 65° above the positive x axis then -B will have the same magnitude but will be 65° below the negative x axis (assuming the vector starts at (0, 0). i.e. both the x and y coordinates will be reversed.
2. 65° East of North is 25° above the positive x-axis!
