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Thanks (: 

 May 2, 2018
 #1
avatar+101952 
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Let  O  = (0,0)

Let A  = (2,3)

Let B = (1,1)

 

Using the "tip to tail" method....let   C  = (2 + 1, 3 + 1)  = (3,4)

 

So......the length of diagonal  OC  =   √ [ (3 - 0)^2  + (4-0)^2  ] =   √[9 + 16 ] = √25  =  5   units

And the length of diagonal AB  = √ [ (2-1)^2 +  ( 3 - 1)^2 ]  = √ [ 1^2  + 2^2]  =  √5 units

 

The perimeter  is   2*OA  = 2 * √ [ 2^2 + 3^2 ] = 2 *√13    +    2* AC  = 2* √ [ (2 - 3)^2 + (3 -4)^2]  = 2 √2

 

So....the total perimeter is     2  [√13  + √2 ]  ≈  10.04  units

 

Here's a pic :

 

 

 

 

 

 

cool cool cool

 May 2, 2018

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