+128472 Let O = (0,0)
Let A = (2,3)
Let B = (1,1)
Using the "tip to tail" method....let C = (2 + 1, 3 + 1) = (3,4)
So......the length of diagonal OC = √ [ (3 - 0)^2 + (4-0)^2 ] = √[9 + 16 ] = √25 = 5 units
And the length of diagonal AB = √ [ (2-1)^2 + ( 3 - 1)^2 ] = √ [ 1^2 + 2^2] = √5 units
The perimeter is 2*OA = 2 * √ [ 2^2 + 3^2 ] = 2 *√13 + 2* AC = 2* √ [ (2 - 3)^2 + (3 -4)^2] = 2 √2
So....the total perimeter is 2 [√13 + √2 ] ≈ 10.04 units
Here's a pic :
