for this i made R=(p−65−2p)
since r is paralel to (1−3)
i did 1= K(p-6) and -3= K(5-2p)
and through simultaneous equation i got k =7
but it was obvious that it is wrong please help thanks
R=F1+F2=(p−6)ˆi+(5−2p)ˆjThis is parallel to the vector ˆi−3ˆjThe easiest way to do this is just to equate the slopes5−2pp−6=−315−2p=18−3pp=13
R=(7,−21) which is clearly parallel to (1,−3)
thank you very much!
+845 
