Let a,b,c be vectors such that a×b+b×c+c×a=(−3−124). Find the area of the triangle whose vertices are a,b , and c.
The area of the triangle formed by a,b, and c is given by
12∥(b−a)×(c−a)∥=12∥b×c−b×a−a×c+a×a∥=12∥b×c+a×b+c×a∥=12∥(−3−124)∥
which gives you 13/2 as your final answer.