If a ball is thrown directly upward with a velocity of 28 ft/s, its height (in feet) after t seconds is given by y = 28t − 16t2. What is the maximum height attained by the ball? (Round your answer to the nearest whole number.)
+36916 Maximum height will occur at TIME t = - b/2a a = -16 b = 28
this is the TIME of maximum height .....substitute tis value of time into the equation for 't' to calculate the maximum HEIGHT
+36916 Maximum height will occur at TIME t = - b/2a a = -16 b = 28
this is the TIME of maximum height .....substitute tis value of time into the equation for 't' to calculate the maximum HEIGHT
