If a ball is thrown directly upward with a velocity of 28 ft/s, its height (in feet) after t seconds is given by y = 28t − 16t2. What is the maximum height attained by the ball? (Round your answer to the nearest whole number.)

Guest May 19, 2020

#1**+2 **

Maximum height will occur at TIME t = - b/2a a = -16 b = 28

this is the TIME of maximum height .....substitute tis value of time into the equation for 't' to calculate the maximum HEIGHT

ElectricPavlov May 19, 2020

#1**+2 **

Best Answer

Maximum height will occur at TIME t = - b/2a a = -16 b = 28

this is the TIME of maximum height .....substitute tis value of time into the equation for 't' to calculate the maximum HEIGHT

ElectricPavlov May 19, 2020