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If a ball is thrown directly upward with a velocity of 28 ft/s, its height (in feet) after t seconds is given by y = 28t − 16t2. What is the maximum height attained by the ball? (Round your answer to the nearest whole number.)

 May 19, 2020

Best Answer 

 #1
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Maximum height will occur at TIME   t = - b/2a           a = -16   b = 28

 

this is the TIME of maximum height    .....substitute tis value of time into the equation for 't' to calculate the maximum HEIGHT

 May 19, 2020
 #1
avatar+23566 
+2
Best Answer

Maximum height will occur at TIME   t = - b/2a           a = -16   b = 28

 

this is the TIME of maximum height    .....substitute tis value of time into the equation for 't' to calculate the maximum HEIGHT

ElectricPavlov May 19, 2020

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