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(2cos2x)/sin2x=cotx-tanx

 Nov 2, 2015
 #1
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(2cos2x)/sin2x=cotx-tanx

 

[ 2(cos^2x - sin^2x)] /  [2sinxcosx]  =

 

cos^2x / [ sinx cosx ]  -  sin^2x / [ sinx cosx]  =

 

cosx / sinx   -  sinx / cosx  =

 

cotx - tanx

 

 

cool cool cool 

 Nov 2, 2015

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