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sec^2-1/sec^2=sin^2... Help please?

Guest Mar 3, 2015

Best Answer 

 #1
avatar+90058 
+5

sec^2-1/sec^2=sin^2x

tan^2x / sec^2x =

[sin^2x / cos^2x]  *  1 / sec^2x =

[sin^2x / cos^2x]  *  cos^2x

sin^2x

 

CPhill  Mar 3, 2015
 #1
avatar+90058 
+5
Best Answer

sec^2-1/sec^2=sin^2x

tan^2x / sec^2x =

[sin^2x / cos^2x]  *  1 / sec^2x =

[sin^2x / cos^2x]  *  cos^2x

sin^2x

 

CPhill  Mar 3, 2015

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