Find the vertex of the graph of the equation $x - y^2 + 8y = 13 + 2y + y^2 - 7y - 14$.
Rewrite as
x = 2y^2 - 13y -1
The y coordinate of the vertex is - (-13) / ( 2*2) = 13/4
The x coordinate is
2(13/4)^2 -13(13/4) - 1 =
-177/8
Vertex = ( -177/8 , 13/4)
+1557 
