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Find the vertex of the graph of the equation $x - y^2 + 8y = 13 + 2y + y^2 - 7y - 14$.

 Mar 2, 2024
 #1
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Rewrite as

 

x =  2y^2  - 13y  -1

 

The y coordinate of the vertex  is    - (-13)  / ( 2*2) = 13/4

 

The x coordinate is

 

2(13/4)^2 -13(13/4) - 1  =   

 

-177/8

 

Vertex = ( -177/8 , 13/4)

 

cool cool cool

 Mar 3, 2024

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