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Find the vertex of the graph of the equation x + y^2 + 6y = 12.

 Oct 21, 2020
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x = -y^2 -6y+12    this is a sideways parabola opening the left

    y coordinate of the vertex is   - b/2a    =     -  -6/(2(-1)) = - 3

    x coordiante will be found b plugging this y value into the equation   x = 21

 Oct 21, 2020

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