Find the vertex of the graph of the equation x + y^2 + 6y = 12.
x = -y^2 -6y+12 this is a sideways parabola opening the left
y coordinate of the vertex is - b/2a = - -6/(2(-1)) = - 3
x coordiante will be found b plugging this y value into the equation x = 21
+36916 
