http://tinypic.com/view.php?pic=24xm2x3&s=9
If you click that link there should be pictures of the two triangles. Thanks.
Δ ABC ~ Δ DEC ....so...
Your first answer is good.....let's examine the rest....
B. tan < A = cot <ECD
BC / AB = CD / ED ??? this isn't true.....
BC /AB = EC/ED
C. sec < ACB = csc D
AC / BC = CD / EC ?? this is true.....
D. sin < CAB = cos < DCE Δ ABC ~ Δ DEC
BC / AC = EC / CD ??? this is true, as well
So....it looks as though A C and D are correct